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Submitted by Dr. Leo Sparks on
CONFIDENTIAL: FIELD NOTE #1

The Dance of Two Frequencies

Investigating the Non-Linear Mixing of Sinusoids

A DEEP DIVE BY DR. LEO SPARKS

Every spark starts with a question! Today, Mr. Ohm and I are not just looking at the surface of the pond; we are diving to the bottom. We know that multiplying signals creates new frequencies. But why? And why does multiplying two Sines give us Cosines?

To understand this, we have to stop thinking about waves as "wiggles" and start thinking of them as rotating vectors (or "phasors," if you want to sound fancy at parties).

The Geometry of Rotation

Forget the time axis for a second. Imagine a clock hand spinning around. The tip of that hand traces a circle. If you look at that circle from the side, you see a wave moving up and down. That is our signal.

When we multiply two signals, we are effectively taking the length of one clock hand and scaling it by the position of another clock hand spinning at a different speed. The result is that the "combined" hand can't decide which way to spin—so it splits into two counter-rotating vectors.

The Mathematical Derivation

Let's convert our frequency $f$ into angular frequency, denoted by the Greek letter $\omega$ (omega), where $\omega = 2\pi f$. This makes the algebra much cleaner.

We start with two signals:

  • $v_1(t) = A \sin(\omega_1 t)$
  • $v_2(t) = B \sin(\omega_2 t)$

When we mix them, we multiply them. Let's assume amplitude $A = B = 1$ for simplicity:

The Goal: Calculate $\sin(\omega_1 t) \cdot \sin(\omega_2 t)$


Recall the trigonometric subtraction formulas:

1) $\cos(A - B) = \cos A \cos B + \sin A \sin B$
2) $\cos(A + B) = \cos A \cos B - \sin A \sin B$

Subtract equation (2) from equation (1):

$\cos(A - B) - \cos(A + B) = 2 \sin A \sin B$

Therefore, solving for our signals:

$$\sin(\omega_1 t) \sin(\omega_2 t) = \frac{1}{2} [\cos(\omega_1 t - \omega_2 t) - \cos(\omega_1 t + \omega_2 t)]$$

Look closely at the result! We started with Sines, but we ended up with Cosines. This tells us there is a 90-degree phase shift involved in the mixing process.

More importantly, the inputs $\omega_1$ and $\omega_2$ are gone. They have been replaced by the difference $(\omega_1 - \omega_2)$ and the sum $(\omega_1 + \omega_2)$.

Visualizing the Spectrum

If we looked at this on a Spectrum Analyzer, we would see two new spikes pushing outward from the center.

Input AInput BResult 1 (Difference)Result 2 (Sum)
1,000 Hz1,200 Hz200 Hz
(The Beat)
2,200 Hz
(The Buzz)

MR. OHM’S PRACTICAL CORNER:

"Leo loves the math, but here is the trap: The 'Difference' frequency can get messy. If $f_1$ is very close to $f_2$, the difference becomes almost zero (DC). In audio, this sounds like a weird 'wobble' or beat note. Filters are your friends, people!"

The Eureka Moment

Great Galloping Galvanometers! The math proves that multiplication is the engine of transformation. This simple trigonometric identity is the reason we have Wi-Fi, Bluetooth, and radio astronomy.

Stay curious, calculate carefully, and keep those circuits humming!

- Dr. Leo Sparks